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10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X ?
A. `"6 g mol"^(-1)`
B. `"60 g mol"^(-1)`
C. `"36 g mol"^(-1)`
D. `"32 g mol"^(-1)`

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Correct Answer - C
No. of moles of urea = `10/60=1/6`
Weight of solute , X=6 g
No. of moles of X =`6/M`
For isotonic solutions, `n_1=n_2` or `1/6=6/M` or `M=36 g mol^(-1)`

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