Correct Answer - D
The ionic reactions are : 2/3 x `(2Al^(3+)) + 4e^(-) to ` 4/3 Al
2/3 x `(3O^(2-)) to O_2 + 4e^(-)`
Thus, no of electrons transferred, n=4, `DeltaG`= -nFE = - 4 x 96500 x E
or 966 x `10^3`= -4 x 96500 x E
`rArr E= - (966xx10^3)/(4xx96500)`=-2.5 V