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`a xx [axx(axxb)]` is equal to

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`a xx [axx(axxb)]` is equal to
A. `(a xx a).(b xx a)`
B. `a. (b xx a)-b (a xx b)`
C. `[a. (a xx b)]a`
D. `(a.a) (b xx a)`
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Correct Answer - C
`axx[axx(axx)]=a{(a*b)a-(a*a)b}`
`=0-(a*a)(axxb)=(a*a)(bxxa)`
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