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All Cu(II) halides are known except the iodide. The reason for it is that
A. iodide is a bulky ion
B. `Cu^(2+)` oxidizes iodide to iodine
C. `Cu_((aq))^(2+)` has much negative hydration enthalpy
D. `Cu^(2+)` ion has smaller size.

1 Answer

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Best answer
Correct Answer - B
`2Cu^(2+)+4I^(-)to 2CuI_2`
The `CuI_2` immediately decomposes to liberate `I_2` and insoluble copper (I) iodide.
`2CuI_2to 2CuI+I_2`

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