Question

If the osmotic pressure of glucose solution is 1.52 bar at 300 K. What would be its concentration if R = 0.083L bar `"mol"^(-1)"K"^(-1)` ?

Answer 1

`pi = "CRT"`
`R=0.0836."bar. mole"^(-1)"K"^(-1)`
T = 300 K
`pi = 1.52" bar"`
`C = (pi)/("RT")=(1.52)/(0.083xx300)=(1.52)/(24.9)=0.061" M"`