Question

Calculate the equilibrium constant of the reaction :
`Cu_((s))+2Ag_((aq))^(+)to Cu_((aq))^(2+)+2Ag_((a))`
`E_((cell))^(Θ)=0.46V`

Answer 1

`E_((cell))^(Θ)=(0.059V)/(2)log K_(c) =0.46V or `
`log K_(c) =(0.46Vxx2)/(0.059V)=15.6`
`K_(c)=3.92xx10^(15)`