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If excess of `AgNO_(3)` solution is added to 100mL of a 0.024 M solution of dichlorobis (ethylenediamine) cobalt (III) chloride . How many mole of AgCl be precipitated ?
A. `0.0012`
B. `0.0016`
C. `0.0024`
D. `0.0048`

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Correct Answer - C
`Co^(3+) + 2 Cl^(-) + 2 (en)`
net charge = +1
Thus , complex is
`[Co(en)_(2) Cl_(2)]^(+) Cl^(-) to [Co(en)_(2) Cl_(2)]^(+) + Cl^(-)`
Only one `Cl^(-)` which is precipitated as AgCl
100 mL of 0.024 M complex = 2.4 millimol = 0.0024 mol

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