Question

How is `E^(0)` cell related mathematically to the equilibrium constant `K_(c)` of the cell reaction ?

Answer 1

Relation between `E_(0)` cell and equilibrium constant `K_(C)` of the cell reaction
`E_(cell)^(0)=(2.303RT)/(nF)log K_(C)`
N = number of electrons involved
F = Faraday = `96500 C mol ^(-1)`
T = Temperature
R = gas constant