Question

Show that the expression of the time period T of a simple pendulum of length l given by `T = 2pi sqrt((l)/(g))` is dimensionally correct

A. Right
B. Wrong
C. Information incomplete
D. None of these

Answer 1

Correct Answer - A
Give, `T=2pisqrt(l)/(g)`
Dimensionally `[T]=sqrt(([L])/([LT^(-2)]))=[T]`
As in the above equation, the dimensions of both side are same. Therefore, the given formula is dimensionally correct.