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The radius of a ball is `(5.2pm0.2)` cm. The percentage error in the volume of the ball is (approximately).

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The radius of a ball is `(5.2pm0.2)` cm. The percentage error in the volume of the ball is (approximately).
A. 0.11
B. 0.04
C. 0.07
D. 0.09
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Correct Answer - A
Radius of ball=5.2cm
`V=(4)/(3)piR^(3)implies(DeltaV)/(V)=3((DeltaV)/(R))`
`((DeltaV)/(V))xx100=3((0.2)/(5.2))xx100=11%`
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