How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms

Correct Answer - B
As, equation of motion is
`v=u+at implies 20 =0+a xx 10`
`20=a xx10 implies a=2 m//s^(2)`
Now, distance `s=ut+1/2 at^(2)`
`implies s=0+1/2 xx2xx10xx10`
or `s=100 m`
`W=F.s ="mas"=50xx2xx100=10^(4) J`

How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms^(-1)` is 10 s?

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