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Predict the number of unpaired electrons in the square planar `[Pt(CN)_(4)]^(2-)` ion.

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`""_(78)Pt` is present in group 10 of the Periodic Table. Its outer configuration is `5d^(9)6s^(1)`
image
For square plannar shape, the hybridization is `dsp^(2)` Hence, the unpaired electrons in 5dorbital pair up to make one d-orbital empty for `dsp^(2)` hybridization. Thus, there is no unpaired electron.

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