Question

The displacement of two particles executing SHM are represented by equations, `y_(1)=2 sin (10 t + theta), y_(2)=3 cos 10 t`. The phase difference between the velocity of these particles is
A. `theta`
B. `-theta`
C. `theta + pi//2`
D. `theta - pi//2 `

Answer 1

Correct Answer - D
We can find the velocities,
`V_(1) = (dy_(1))/(dt) = 2 xx 10 cos (10 t + theta)`
and `V_(2) = - 3 xx 10 sin 10 t = 30 cos (10 t + pi//2)`
`therefore` Phase difference `= (10 t + theta) - (10 t + pi//2)= theta - pi//2`