Question

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.
A. T/2
B. T/4
C. T/8
D. T/12

Answer 1

Correct Answer - D
`y = a sin omega t = "a sin"(2pi)/(T).t`
At the mean position, `(a)/(2)=a "sin"(2pi)/(T)t`
`rArr" "(1)/(2)="sin"(2pi)/(T)t`
`rArr" "(pi)/(6)=(2pi)/(T)t`
`rArr" "t=(T)/(12)`