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The velocity of a particle performing simple harmonic motion, when it passes through its mean position i
A. infinity
B. zero
C. minimum
D. maximum

1 Answer

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Correct Answer - D
The relation for velocity of a particle executing SHM is given by, `v = omega sqrt(A^(2) - y^(2))`. Hence, at mean position y = 0.
The velocity is maximum. `V_(max) = A omega` (where, A is amplitude)

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