Question

A tangential force of 0.25 N is applied to a 5 cm cube to displace its upper surface with respect to the bottom surface. The shearing stress is
A. `10 Nm^(-2)`
B. `50 Nm^(-2)`
C. `75 Nm^(-2)`
D. `100 Nm^(-2)`

Answer 1

Correct Answer - d
Shearing stress
`= (F)/(A) = (25 xx 10^(-2))/(25 xx 10^(-4)) = 100 Nm^(-2)`