Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
978 views
in Physics by (97.1k points)
closed by
The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as `x=0.05cos(4pit+(pi)/4)` .the frequency of the motion will be
A. 0.5 Hz
B. 1.0 Hz
C. 1.5 Hz
D. 2.0 Hz

1 Answer

0 votes
by (97.1k points)
selected by
 
Best answer
Correct Answer - D
Compare the given equation with the standard from
`y=a cos [(2pi t)/T-(2pi x)/lambda]`
Coefficient of `t=(2pi)/T=2 pi n=4 pi, n =2` Hz

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...