Question

When two tuning forks (fork `1` and fork `2` ) are sounded simultaneously, `4` beats per second are heard. Now, some tape is attached on the prong of the fork `2`. When the tuning forks are sounded again, `6` beats per second are heard. If the frequency of fork `1` is `200 Hz`, then what was the original frequency of fork `2` ?
A. 196 Hz
B. 200 Hz
C. 202 Hz
D. 204 Hz

Answer 1

Correct Answer - A
Here, `n_(1)=200` Hz
Number of beats `s^(-1), m=4`
`:. n_(2)=200 pm 4=204` or 196 Hz
On loading fork 2, its frequency decreases. And number of beats per second increases to 6. Therefore, m is negative, `n_(2)=200-4=196` Hz