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A cylinderical tube open at both ends, has a fundamental frequency f in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of air column is now
A. `3f_(0)//4`
B. `f_(0)`
C. `f_(0)//2`
D. `2f_(0)`

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Correct Answer - b
As, `n_("open")=v/(2l_("open"))`
and `n_(closed)=v/(4l_(closed))`
`=v/(4l_(open)//2) (l_(closed)=l_(open)/2)`
i.e. frequency remain unchanged.

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