Question

The distance between the first and the sixth minima in the diffraction pattern of a single slit is 0.5 mm. The screen is 0.5 m away from the slit. If the wavelength of light used is 5000 Å. Then the slit width will be
A. 5 mm
B. 2.5 mm
C. 1.25 mm
D. 1.0 mm

Answer 1

Correct Answer - B
Distance between first and sixth minima
`x=(5lambdaD)/(d)`
`therefore d=(5lambdaD)/(x)=(5xx5000xx10^(-10)xx0.5)/(0.5xx10^(-3))`
`d=2.5xx10^(-3)m=2.5mm`