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∫x^x (1 + log x) . dx =

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in Indefinite Integral by (32.4k points)
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∫xx (1 + log x) . dx =

(a) 1/2 (1 + log x)2 + c

(b) x2x + c

(c) xxlog x + c

(d) xx + c

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1 Answer

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Best answer

Correct answer is (d) xx + c

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