∫ (e^2x + e^-2x)/(e^x) .dx =

Question

\(\int \frac{e^{2x} + e^{-2x}}{e^x}.dx = \)

∫ (e^2x + e^-2x)/(e^x) .dx =

(a) \(e^x - \frac{1}{3e^{3x}} + c\)

(b) \(e^x + \frac{1}{3e^{3x}} + c\)

(c) \(e^{-x} + \frac{1}{3e^{3x}} + c\)

(d) \(e^{-x} - \frac{1}{3e^{3x}} + c\)

Answer 1

Correct answer is (a) \(e^x - \frac{1}{3e^{3x}} + c\)