Here, mean = 80, number of observations = 50
\(Mean = \cfrac{The\,sum \,of\, all \,observatiojns \,in \,the \,data }{Total \,number \,of \,observations}\)
∴ The sum of all observations = Mean x Total number of observations
∴ The sum of 50 observations = 80 x 50 = 4000
One of the observation was 19. However, by mistake it was recorded as 91.
Sum of observations after correction = sum of 50 observation + correct observation – incorrect observation
= 4000 + 19 – 91
= 3928
∴ Corrected mean
= \( \cfrac{sum \,of \,observatiojns \,after \,correction }{Total \,number \,of \,observations}\)
= \(\frac{3928}{50}\)
= 78.56
∴ The corrected mean is 78.56.