Correct Answer - C
Frequency of revolution , ` f=(v)/( 2pir )`
The moving charge is equivalent to a current loop , given by
`l=f xx e or l=(ev)/( 2pir )`
If A be the area of the orbit , then the magnetic moment of the orbiting electron is ,
`M=lA=((ev)/( 2pi r))(pir^(2))=(evr)/(2)`
Putting the values , we get
`M=((1.6 xx 10^(-19))(2.2 xx 10^(6))(5.3 xx 10^(-11) xx 10^(-2)))/(2)`
`=9.3 xx 10^(-26)A-m^(2)`