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A radio transmitter operates at a frequency of `880 kHz` and a power of `10 kW`. The number of photons emitted per second are
A. `10^(27)`
B. `10^(28)`
C. `10^(32)`
D. `10^(30)`

1 Answer

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Best answer
Correct Answer - C
Given, power `P=66kW=66000W`
frequency, v=1000 kHz
Number of photons emitted per second`=(P)/(hv)`
`=(66xx10^(3))/(6.6xx10^(-34)xx(1000xx10^(3)))=10^(32)`.

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