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Energy of photon whose frequency is `10^(12) MHz`, will be
A. `4.14xx10^(3)keV`
B. `4.14xx10^(2)eV`
C. `4.14xx10^(3)MeV`
D. `4.14xx10^(3)eV`

1 Answer

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Best answer
Correct Answer - D
Using the relation, `E=hv=6.63xx10^(-34)xx10^(18)J`
`=(6.63xx10^(-16))/(1.6xx10^(-19))eV=4.14xx10^(3)eV`

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