Question

A coil of inductance 0.50 H and resistance `100Omega` is connected to a 240 V, 50Hz ac supply.
what is the maximum current in the coil?

Answer 1

Given, Inductance L = 0.50 H
Resistance `R = 100 Omega`
`V_("rms")=240V, f=50Hz`
Impedance of circuit
`Z=sqrt(R^(2)+X_(L)^(2))=sqrt(R^(2)+(2pi fL)^(2))`
`= sqrt((100)^(2)+(2xx3.14xx50xx0.50)^(2))`
`= 186.14 Omega`
the rms value of current
`I_("rms")=(V_("rms"))/(z)=(240)/(186.14)1.29 A`
the maximum value of current in the circuit
`I_(0)=sqrt(2)I_("rms")=1.414xx1.29=1.824A`