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Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the

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Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is `620` pm. What is the nearest neighbour distance and what is the redius of xenon atom?
A. 438.5 pm
B. 219.25 pm
C. 420 pm
D. 261.5 pm
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Correct Answer - A
As xenon crystallises in fcc lattice , nearest neighbour
distance (d) `=a/sqrt2=(620)/(sqrt2)=620/1414 = 438.5`
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