Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
66 views
in Chemistry by (97.2k points)
closed by
The anions A from hexagonal close packing and atoms (M) occupy only two-third of the octahedral voids. The general formula of the compound is
A. `M_2A_3`
B. MA
C. `MA_2`
D. `M_3A_2`

1 Answer

0 votes
by (97.1k points)
selected by
 
Best answer
Correct Answer - A
In hexagonal close packing, one sphere is in contact with 12 spheres .
Thus , the number of anion A per unit cel = 12
Octahedral voids = number of spheres = 12
`therefore` number of M atoms per unit cell
`=2/3 " of octahedral voids " = 2//3 xx12 =8`
`rArr` A:M = 12:8=3:2
`therefore " The formula of the compound is " M_2A_3` .

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...