Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
89 views
in Chemistry by (97.1k points)
closed by
Calculate the mass of urea `(NH_(2)CONH_(2))` required in making `2.5 kg `of `0.25 `molal aqueous solution.
A. `37.5g`
B. `73.5g`
C. `53.7g`
D. `75.3g`

1 Answer

0 votes
by (97.1k points)
selected by
 
Best answer
Correct Answer - A
`"Molality"=(("mass")/("molar mass"))/("molar ofsolvent (in kg)")`
`0.25=(("mass")/(60))/(2.5)" "(because" Molar mass of urea = 60")`
`"or Mass"=0.25xx2.5xx60=37.5g`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...