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In a process, `701 J` of heat is absorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?
A. `-464J`
B. `+464J`
C. `+307J`
D. `-307J`

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Correct Answer - C
We know, internal energy change, `DeltaE=q+W`
`=+701J+(-394J)=+307J`.
Hence, internal energy of the system increases by 307 J.

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