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The free energy for a reaction having `DeltaH=31400cal,DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` is

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The free energy for a reaction having `DeltaH=31400cal,DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` is
A. `-9336cal`
B. `-7386cal`
C. `-1936cal`
D. `+9336cal`
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Correct Answer - A
From Gibbs-Helmholtz equation, we know
`DeltaG=DeltaH-T*DeltaS=31400-1273xx32`
`=31400-40736=-9336cal`
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