Question

The pressure of a gas is 100 k Pa. if it is compressed from 1 `m^(3)` to `10 dm^(3)` , find the work done .
A. 99 kJ
B. `-99kJ`
C. `114.9kJ`
D. `-114.9kJ`

Answer 1

Correct Answer - A
Given, number of moles=2moles
`V_(1)=1m^(3)=1000dm^(3),V_(2)=10dm^(3)`
`therefore` We have, work done `(W)=-p_(ext)dV`
`=-100kPaxx(10-1000)dm^(3)` ltBrgt `=-100kPaxx-999dm^(3)`
`=99900J=99.9kJ`