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The rate of formation of `SO_(3)` in the following reaction is `100 g " min"^(-1).2SO_(2)+O_(2)rarr2SO_(3)`
The rate of disappearance of `O_(2)` is
A. 29 g `"min"^(-1)`
B. 20 g `"min"^(-1)`
C. 200 g `"min"^(-1)`
D. 50 g `"min"^(-1)`

1 Answer

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Best answer
Correct Answer - B
`2SO_(2)+O_(2)rarr2SO_(3)`
`Rate=-(d[O_(2)])/(dt)=(1)/(2)(d[SO_(3)])/(dt)`
The rate of formation of S)_(3) is
`(d[SO_(3)])/(dt)=100g min^(-1)=(100)/(80) mol min^(-1)`
`[because "molar mass" of SO_(3)=80 g " mol"^(-1)]`
`(d[O_(2)])/(dt)=(1)/(2)((100)/(80))mol min^(-1)`
`(d[O_(2)])/(dt)=(1)/(2)((100)/(80))xx32gmin^(-1)`
`[because "molar mass of "O_(2)=32g" mol"^(-1)]`
`=20g" min"^(-1)`

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