Question

A first order reaction is 50% completed in 40 minutes at 300 K and in 20 minutes at 320 K. Calculate the activation energy of the reaction. (Given : log2 = 0.3010, log4 = 0.6021, R = 8.314 JK^-1mol^-1)

Answer 1

T₁ = 300 K, t_1/2 = 40 minutes

T₂ = 320 K, t_1/2 = 20 minutes

For, first order t_1/2 = 0.693/k