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Excess of `KI` reacts with `CuSO_(4)` solution and `Na_(2)SO_(3)` solution is added to it. Which of the following statements in incorrect for the reaction?
A. `Cu_2I_2` is reduced
B. Evolved `I_2` is reduced
C. `Na_2S_2O_3` is oxidised
D. `CuI_2` is formed

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Correct Answer - D
`2CuSO_4 + KI "(excess)" to 2K_2SO_4 + Cu_2I_2 + I_2 uarr`
`Na_2S_2O_3 + I_2 to Na_2 S_4 O_6 + 2NaI`

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