Correct Answer - B
Given, `v=50Hz, I_(rms)=5A`
`t=1/300s`
We have to find I(t)
`I_(0)= "Peak value"=sqrt(2), I_(rms)=sqrt(2) xx5`
`=5sqrt(2)` A
`I=I_(0)sinomegat=5sqrt(2)sin2pivt=5sqrt(2)sin 2pi xx 50 xx 1/300`
`=5sqrt(2)sin pi/3=5sqrt(2) xx sqrt(3)/2 = 5sqrt(3//2)` A