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Common oxidation state of Scandium, a transition element is /are (At. No =21)
A. `+4`
B. `+1`
C. `+2` and +3
D. `+4` and +1

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Correct Answer - C
Common oxidation state of Sc (atomic number 21) is +2 `(Sc^(+2) 3d^1 4s^0)` and `+3 (Sc^(+3) 3d^0 4s^0)`

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