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4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molality of the resultant solution is……..
A. `0.004`
B. `0.008`
C. `0.012`
D. `0.016`

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Correct Answer - D
Given, `M_(1)=0.02M,V_(1)=4L, M_(2)=?,V_(2)=4L+1L=5L`
As we know, `" "M_(1)V_(1)=M_(2)V_(2)`
`" "0.02xx4L=M_(2)xx5L`
`" "M_(2)=(0.08)/(5)=0.016M`

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