The reaction of `KMnO_(4)` in which it acts as an oxidising agent in acidic medium is
`2KMnO_(4)+3H_(2)SO_(4) rarrK_(2)SO_(4)+2MnSO_(4)+3H_(2)O+5[O]`
`(H_(2)S+[O]rarrH_(2)O+Sxx5)/(2KMnO_(4)+3H_(2)SO_(4)+5H_(2)SrarrK_(2)SO_(4)+2MnSO_(4)+8H_(2)O+5S)`
5 moles of `S^(2-)` ions react with 2 moles of `KMnO_(4)`. So, 1 mole of `S^(2-)` ion will react with `(2)/(5)` moles of `KMnO_(4)`.