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A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-
A. `42^(@)`
B. `43^(@)`
C. `49^(@)`
D. `6.84^(@)`

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Best answer
Correct Answer - D
`2 pi r =34.3 therefore r= (34.3 )/(2pi) and tan theta=(v^(2))/(rg)`

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