Question

A wire having a linear mass density `5xx10^(-3)` kg/m is stretched between two rigid supports with a tension of 450 N. The wire resibate at a frequency of 420 Hz. The next higher frequency at which the same wire resonates is 490 Hz. Find the length of wire -
A. 2.1 m
B. 1.05 m
C. 4.2 m
D. None of these

Answer 1

Correct Answer - 1
`420=(n)/(2L)sqrt((F)/(mu))`
`490=((n+1))/(2L)sqrt((F)/(mu))`
on solving
n=6
By (i)
L=2.1 m