Question

Corner poins of the feasible region determned by the system of linear constrainsts are (0,3), (1,1), and (3,0). Let Z=px+qy. Where `p, q lt 0` Condition on p and q, so that the minimum of Z occurs at (3,0) and (1,1) is
A. p=2q
B. `p=(q)/(2)`
C. p=3q
D. p=q

Answer 1

Correct Answer - B

So, condition of p and q, so that the minimum of Z occurs at (3,0) and (1,1) is
`p+q=3p Rightarrow 2p=q, p=(q)/(2)`