Question

Two simple harmonic motions are given by `y_(1) = a sin [((pi)/(2))t + phi]` and `y_(2) = b sin [((2pi)/( 3))t + phi]`. The phase difference between these after `1 s` is
A. `pi`
B. `pi//2`
C. `pi//4`
D. `pi//6`

Answer 1

Correct Answer - D
`phi_(2)-phi_(1)=((2pi)/(3)t-(pi)/(2)t)=((2pi)/(3)-(pi)/(2))xx1`
`=((4pi-3pi)/(6))=(pi)/(6)`