Question

When a particle oscillates simple harmonically, its kinetic energy varies periodically. If frequency of the particle is n, the frequency of the kinetic energy is
A. 4 n
B. n
C. 2 n
D. `n//2`

Answer 1

Correct Answer - C
`K.E,=(1)/(2) momega^(2) (A^(2)-x^(2))`
`=(1)/(2) momega^(2) (A^(2)-A^(2) sin^(2)omegat)`
`=(1)/(2) momega^(2)A^(2)(1-sin^(2)omega^(2)omegat)`
`K.E.=(1)/(2)momega^(2)A^(2) ((1+cos2omegat))/(2)`
`therefore` The frequency of its kinetic energy is `2omega`