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Let `A=(4, 0), B=(0, 12)` be two points in the plane. The locus of a point C such that the area of triangle ABC is 18 sq. units is -
A. `(y+3x+12)^(2)=81`
B. `(y+3x+81)^(2)=12`
C. `(y+3x-12)^(2)=81`
D. `(y+3x-81)^(2)=12`

1 Answer

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Best answer
Correct Answer - C
image
`1/2|(1,x,y),(1,0,12),(1,4,0)|= pm 18`
`1(-48)-x(-12)+y(4)= pm 36`
`12x+4y-48=pm 36`
`3x+y-12= pm 9`
`(3x+y-12)^(2)=81`

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