A body of mass 25 gm performs linear S.H.M. The force constant of the motion is 400 dyne/cm. When the body is at a distance of 10 cm from the equilibrium position has velocity of 40 cm/s, then the total energy of the body will be
A. `40xx10^(4)J`
B. `4xx10^(4)erg`
C. `2xx10^(4)erg`
D. `2xx10^(5)J`