Question

Ratio of kinetic energy to potential energy of an oscillator when it is at distance `1//N` times of amplitude from mean positions in
A. `n^(2)`
B. `n^(2)+1`
C. `1//n^(2)`
D. `n^(2)-1`

Answer 1

Correct Answer - D
`(K.E.)/(P.E.)=((1)/(2)momega^(2)(A^(2)-x^(2)))/((1)/(2)momega^(2)x^(2))`
`=(A^(2)-x^(2))/(x^(2))=(A^(2)-(A^(2))/(n^(2)))/((1)/(n^(2))A^(2))=n^(2)-1`