Correct Answer - D
`underline({:(126=lambda_(Na^(+))^(oo),+lambda_(Cl^(-))^(oo)),(150=lambda_(K^(+))^(oo),+lambda_(Cl^(-))^(oo)),(250=lambda_(Na^(+))^(oo),+lambda_(OH^(-))^(oo)):})`
`(150+250-126)=lambda_(K^(+))^(oo)+lambda_(OH^(-))^(oo)`
`or lambda_(KOH)^(oo)=274`