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Two wires whose lengths are in ratio 3:2 are stretched with equal tension and give equal frequency . If the radii of the wires are in the ratio 3:2, then the ratio of densities of the wires is
A. `81:16`
B. `4:9`
C. `16:81`
D. `9:4`

1 Answer

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Best answer
Correct Answer - C
As `n_1 = n_2`
`l_1/l_2xxr_1/r_2 = sqrt(rho_2/rho_1)`
`3/2xx3/2 = sqrt(rho_2/rho_1)`
`9/4=sqrt(rho_2/rho_1)`
`81/16 = rho_2/ rho_1 therefore rho_1/rho_2= 16/81`

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